Sharpsville Map
Sharpsville is a town in Liberty Township, Tipton County, Indiana, in the United States. It is part of the Kokomo, Indiana Metropolitan Statistical Area. As of the 2010 census, Sharpsville's population is 607.
Sharpsville is located at 40°22?44?N 86°5?12?W / 40.37889°N 86.08667°W / 40.37889; -86.08667 (40.378949, -86.086632). According to the United States Census Bureau, the town has a total area of 0.2 square miles (0.6 km²), all of it land.
As of the census of 2000, there were 618 people, 232 households, and 179 families residing in the town. The population density was 2,795.4 people per square mile (1,084.6/km²). There were 243 housing units at an average density of 1,099.1 per square mile (426.5/km²). The racial makeup of the town was 98.54% White, 0.32% African American, 0.16% Asian, 0.32% Pacific Islander, 0.49% from other races, and 0.16% from two or more races. Hispanic or Latino of any race were 1.29% of the population.
Nearby cities include Russiaville, Atlanta, Arcadia, Elwood, Galveston.